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When two concentric shells are connected...

When two concentric shells are connected by a thin conducting wire, whole of the charge of inner shell transfers to the outer shell and potential difference between them becomes zero. Surface charge densities of two thin concentric spherical shells are `sigma` and `-sigma` respectively. Their radii are R and `2R`. Now they are connected by a thin wire.

Potential on either of the shells will be :-

A

`-(3sigmaR)/(2epsilon_(0))`

B

`-(2sigmaR)/(2epsilon_(0))`

C

`-(sigmaR)/(2 epsilon_(0))`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
`Q_(1)=sigmaxx4piR^(2)`
`Q_(2)=-sigmaxx4pi(2R)^(2)=-4Q_(1)`
Potential at outer shell
`=(K[Q_(1)-Q_(2)])/(2R)=(K[Q_(1)-4Q_(1)])/(2R)`
`=(-1xx3xxsigmaxx4piR)/(4pi in_(0)xx2R)=-3/2sigma/in_(0)xxR`
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