Home
Class 11
PHYSICS
A cavity pf radius r is present inside a...

A cavity pf radius `r` is present inside a solid dielectric sphere of radius ` R`, having a volume charge density of ` rho`. The distance between the centres of the sphere and the cavity is a . An electron `e` is kept inside the cavity at an angle ` theta = 45^@` as shown . how long will it take to touch the sphere again ?
.

Text Solution

Verified by Experts

The correct Answer is:
`sqrt((6sqrt(2)mr in_(0))/(e rho a))`

The direction of electric field inside the cavity in -ve x direction and of constant magnitude `(rho a)/(3 in_(0))`

For touch the sphere again, electron must move `2r cos 45^(@)` (as shown) distance
`:. 1/2 [(rho a)/(3 in_(0))xxe/m]xxt^(2)=sqrt(2)r :. t=sqrt((6sqrt(2)mr in_(0))/(e rho a))`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS

    ALLEN|Exercise Exercise-05(A)|35 Videos
  • MISCELLANEOUS

    ALLEN|Exercise Exercise-05(B)|19 Videos
  • MISCELLANEOUS

    ALLEN|Exercise Exersice-04[A]|34 Videos
  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-7|8 Videos
  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN|Exercise EXERCISE-IV|8 Videos

Similar Questions

Explore conceptually related problems

A cavity of radius r is present inside a solid dielectric sphere of radius R, having a volume charge density of rho . The distance between the centres of the sphere and the cavity is a. An electron e is kept inside the cavity at an angle theta=45^(@) as shown. the electron (mass m and -e) touches the sphere again after time ((P sqrt(2) mr epsi_(0))/(e a rho))^(1//2) ? Find the value of P. Neglect gravity.

A cavity of radius r is present inside a fixed solid dielectric sphere of radius R, having a volume charge density of rho . The distance between the centres of the sphere and the cavity is a. An electron is released inside the cavity at an angle theta = 450 as shown. The electron (of mass m and charge –e) will take ((Psqrt(2)mrepsilon_(0))/(earho))^(1//2) time to touc the sphere again. Neglect gravity. find the value of P:

A solid non-conducting sphere of radius R is charged with a uniform volume charge density rho . Inside the sphere a cavity of radius r is made as shown in the figure. The distance between the centres of the sphere and the cavity is a. An electron of charge 'e' and mass 'm' is kept at point P inside the cavity at angle theta = 45^(@) as shown. If at t = 0 this electron is released from point P, calculate the time it will take to touch the sphere on inner wall of cavity again.

A solid conducting sphere of radius r is having a charge of Q and point charge q is a distance d from the centre of sphere as shown. The electric potential at the centre of the solid sphere is :

A smooth chute is made in a dielectric sphere of radius R and uniform volume charge density. rho . A charge particle of mass m and charge -q is placed at the centre of the sphere. Find the time period of motion of the particle?

The figure represents a solid uniform sphere of mass M and radius R . A spherical cavity of radius r is at a distance a from the centre of the sphere. The gravitational field inside the cavity is

A hemispherical cavity of radius R is created in a solid sphere of radius 2R as shown in the figure . Then y -coordinate of the centre of mass of the remaining sphere is

Potential difference beween centre and surface of the sphere of radius R and uniorm volume charge density rho within it will be

A sphere of radius R contains charge density rho(r )=A (R-r ) , for 0 lt r lt R . The total electric charge inside the sphere is Q. The electric field inside the sphere is

Inside a uniform sphere of density rho there is a spherical cavity whose centre is at a distance l from the centre of the sphere. Find the strength of the gravitational field inside the cavity.