A gaseous mixture of methane and heptane is 8.25 ratio (by weight) respectively is allowed to effuse through a pin ole in the flask. How many methane molecules would come out by the time when the first molecule of heptane is out?
Text Solution
Verified by Experts
The correct Answer is:
5
Topper's Solved these Questions
STATES OF MATTER
IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise MATCH THE COLUMNS|1 Videos
SOME BASIC CONCEPTS OF CHEMISTRY
IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Subjective Questions|2 Videos
SURFACE CHEMISTRY
IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise JEE Main And Advanced|17 Videos
Similar Questions
Explore conceptually related problems
A certain gaseous mixture contains methane and sulphur dioxide in ratio of 1:8 by mass. The ratio of the number of molecules is :-
The gas 'A' decomposes as A rarr B + 5C A partially decomposed gaseous mixture is allowed to effuse through a pin hole and the gas coming out initially was analysed. The mole fraction of C in effused gas was found to be 0.6. Determine : (a) ratio of ratio of effusion of 'C' and 'B' (b) the precentage of dissociation of 'A'. (Give answer excluding the decimal places) [Given : Molecular mass of A = 360, Molecular mass of C = 40] Hence, fill OMR answer of (a) and (b) with the value of ((b))/((a))
A mixture of 0.5 mole of CO and 0.5 mole of CO_(2) is taken in a vessel and allowed to effuse out through a pinhole into another vessel which has vacuum If a total of A mole has effused out in time t show that M_(1)A +M_(2) (1-A) =36 where M_(1) and M_(2) are mean molar masses of the mixture that has effused out and the mixture still remaining in vessel respectively .
Knowledge Check
A gaseous mixture containing He,CH_(4) and SO_(2) was allowed was allowed to effuse through a fine hole then find what molar ratio of gases coming out initially ? If mixture contain He, CH_(4) and SO _(2) in 1:2:3 mole ratio.
A
`2:2:3`
B
`6:6:1`
C
`sqrt(2):sqrt(2):3`
D
`4:4:3`
A mixture of H_(2)andO_(2) taken in a bulb in 2 : 1 mole ratio is allowed to diffuse through a fine hole. The composition of the gases (mole ratio) coming out initially is 8 : 1. The composition of the gases after some time may be
A
`8:1`
B
`9:1`
C
`7:1`
D
`4:1`
A gaseous mixture containing He, CH_(4) and SO_(2) was allowed to effuse through a fine hole. If mixture contain He, CH_(4) and SO_(2) in 1 : 2 : 3 mole ratio, calculate the molar ratio of gases effusing out initially.
A
`2:2:3`
B
`6:6:1`
C
`sqrt2:sqrt2:3`
D
`4:4:3`
IIT-JEE PREVIOUS YEAR (CHEMISTRY)-STATES OF MATTER-INTEGER_TYPE
