If `3(cos 2phi-cos2theta)=1-cos2phi cos2theta`, then `tan theta= k tan phi`, where `theta, phiin (0,(pi)/(2))`, where k =

Find the value of k from the following relations : 3 ( cos 2 phi - cos 2 theta) = 1- cos 2 theta cos phi , tan theta = ktan phi "where" theta and phi" are acute angles"

From the relation 3(cos2 phi-2 theta)=1-cos2 phi cos2 theta we get tan theta=k tan phi Find the value of k^(4)

From the relation 3(cos2 phi-2 theta)=1-cos2 phi cos2 theta we get tan theta=k tan phi Find the value of k^(4)

If cos(theta+phi)=m cos(theta-phi) then tan theta is equal to

If a cos phi=b cos theta, show that a tan theta+b tan phi=(a+b)tan((theta+phi)/(2))

If cos theta=(2 cos phi-1)/(2-cos phi) , then tan (theta)/(2)=

If " "a cos phi = b cos theta," show that " a tan theta + b tan phi = (a+b) tan ((theta + phi)/2)

If sin theta=(1)/(2)cos phi=(1)/(3) then theta+phi belogs to where 0

If cos theta =(a cos phi+b)/(a+bcosphi) then ("tan"(theta)/2)/("tan"(phi)/2)=