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(1)/(4)" and "(1)/(3)...

(1)/(4)" and "(1)/(3)

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(1)/(4)" " (1)/(2) " "(3)/(4)" "1" "1(1)/(4)" "1(1)/(2)" "1(3)/(4) ?

The sum of the infinite series (1)/(2) ((1)/(3) + (1)/(4)) - (1)/(4)((1)/(3^(2)) + (1)/(4^(2))) + (1)/(6) ((1)/(3^(3)) + (1)/(4^(3))) - ...is equal to

The square root of ((3 (1)/(4))^4-(4 (1)/(3))^4)/((3(1)/(4))^2-(4(1)/(3))^2) is

The sum of the series 1 + (1)/(1!) ((1)/(4)) + (1.3)/(2!) ((1)/(4))^(2) + (1.3.5)/(3!) ((1)/(4))^(3)+ ... to infty , is

The sum of the series 1 + (1)/(1!) ((1)/(4)) + (1.3)/(2!) ((1)/(4))^(2) + (1.3.5)/(3!) ((1)/(4))^(3)+ ... to infty , is

The sum of the first 35 terms of the series (1)/(2) + (1)/(3) -(1)/(4) -(1)/(2) -(1)/(3) +(1)/(4) +(1)/(2) + (1)/(3) -(1)/(4)

1+ (1) / (4) + (1) / (4) (3) / (8) + (1) / (4) (3) / (8) (5) / (12) + ... . + oo

1+(1)/(4) + (1.3)/(4.8) + (1.3.5)/(4.8.12)+…...=

The sum of the first 35 terms of the series (1)/(2)+(1)/(3)-(1)/(4)-(1)/(2)-(1)/(3)+(1)/(4)+(1)/(2)+(1)/(3)-(1)/(4) is -(1)/(2)(b)-(1)/(4) (c) (1)/(4) (e) None of these