y^(2)-7x+12

(i) x^(2)-7x+12=0 (ii) y^(2)+y-12=0

Add the algebraic expressions: 4xy^(2)-7x^(2)y,12x^(2)y-6xy^(2),-3x^(2)y+5xy^(2)

In the following questions two equation numbered I and II are given You have to solve both equations and . . . . . (i) x^(2)-7x+12=0 (ii) y^(2)-12y+32=0

A= {x//x^(2) -7x +12 =0}, B= {x//x^(2) -x-12=0}, then AnnB=

A= {x//x^(2) -7x +12 =0}, B= {x//x^(2) -x-12=0}, then AnnB=

The system y^(x^(2)+7x+12)=1 and x+y=6,y>0 has

If the equation 2x^(2)+4xy+7y^(2)-12x-2y+t=0, where t is a parameter has exactly one real solution of hte form (x,y), then hte sum of (x+y) is equal to

I. 10x^(2) - 7x + 1= 0" " II. 35y^(2) - 12y + 1 = 0

I. x^(2) - 7x + 10 = 0" "II. Y^(2) - 12y + 35 = 0

I. x^(2) -7x + 12 = 0" "II. 3y^(2) - 11y + 10 = 0