" If "f(x)=sum_(lambda=1)^(n)(x-(5)/(lambda))(x-(4)/(lambda+1))" ,then "tim f(0)" is equal to "

If f(x)=sum_(lambda=1)^(n)(x-(5)/(lambda))(x-(4)/(lambda+1)) then lim_(n rarr oo)f(0) is equal to

If f(x)=sum_(lambda=1)^(n)(x-(5)/(lambda))(x-(4)/(lambda+1)) then lim_(n rarr oo)f(0) is equal to

If f(x)=|(x,lambda),(2lambda,x)| , then f(lambdax)-f(x) is equal to

lim_(lambda rarr0)(int_(0)^(1)(1+x)^(lambda)dx)^((1)/(lambda)) is equal to

If f(x)=(2018x-2019)/(x+lambda) and f(f(x))=x then lambda=

If the range of f(x) =cos^(-1)[5x] is {a, b,c} and a+b+c = (lambda pi)/(2) , then lambda is equal to ([.] denotes G.I.F.)

If the range of f(x) =cos^(-1)[5x] is {a, b,c} and a+b+c = (lambda pi)/(2) , then lambda is equal to ([.] denotes G.I.F.)

If the area (in sq.units) bounded by the parabola y^(2)=4 lambda x and the line y=lambda x,lambda>0, is (1)/(9), then lambda is equal to:

If f:R^(+)rarrA , where A={x:-5ltxltoo} is defined by f(x) = x^(2) - 5 and if f^(-1)(13)={-lambdasqrt((lambda-1)),lambdasqrt((lambda-1))} , the value of lambda is