For the given reaction:
`H_(2) + I_(2) rarr 2HI`
Given: `{:(T(K),1//T(K^(-1)),log k,),(769,1.3 xx 10^(-3),2.9,),(67,1.5 xx 10^(-3),1.1,):}`
The activation energy will be

The rate constants for a reaction at 400 K and 500 K are 2 . 60 xx 10^(-5) s^(-1) and 2.60 xx 10^(-3) s^(-1) respectively. The activation energy of the reaction in kJ mol^(-1) is

For the reaction A rarr B , the rate constant k (in s^(-1) ) is given by log_(10) k = 20.35 - ((2.47 xx 10^(3)))/(T) The energy of activation in kJ mol^(-1) is ________ . (Nearest integer) [Given : R = 8.314 J K^(-1) mol^(-1) ]

The [H^(+)] of 0.10 MH_(2)S solution is (given K_(1)=1.0 xx 10^(-7) , K_(2)=1.0 xx 10^(-14))

The specific reaction rates of a chemical reaction are 2.45xx10^(-5)sec^(-1) at 273 K and 1.62xx10^(-4)sec^(-1) at 303 K. Calculate the activation energy.

The specific reaction rates of a chemical reaction are 2.45xx10^(-5)sec^(-1)" at "273K and 16.2 xx10^(-4) sec^(-1) at 303 K. Calculate the activation energy.

The specific reaction rates of a chemical reaction are 2.45xx10^(-5)sec^(-1)" at "273K and 16.2 xx10^(-4) sec^(-1) at 303 K. Calculate the activation energy.

The specific reaction rates of a chemical reaction are 2.45xx10^(-5)sec^(-1)" at "273K and 16.2 xx10^(-4) sec^(-1) at 303 K. Calculate the activation energy.

The rate constant of a reaction at 300 K is 1.6 xx 10^(-3) sec^(-1) and at 310K it is 3.2 xx 10^(-3) sec^(-1) the activation energy of the reaction approximately in kcals is

The rate of constant of reaction at 300 K//320 K are 5 xx 10^(-4) s^(-1) and 2.0 xx 10^(-3)s^(-1) respectively. Calculate the value of activation energy of reaction.