Figure shown two blocks in contact sliding down an inclined surface of inclination `30^(@)`. The block of mass `2 kg `and the incline is `mu_(1) = 0.20` and the incline is `mu_(2) = 30` .Find the acceleration of `2.0 kg` block `g = 10 ms^(-2)`

Figure shown two blocks in contact sliding down an inclined surface of inclination 30^(@) . The block of mass 2 kg and the incline is mu_(1) = 0.20 and the incline is mu_(2) = 0.30 .Find the acceleration of 2.0 kg block g = 10 ms^(-2)

Figure shown two blocks in contact sliding down an inclined surfase of inclination 30^(@) . The friction coefficient between the block of mass 4.0kg and the incline is mu _(2) =0.30 . Find the acceleration of 2.0kg block. (g = 10m//s^(2))

Figure shown two blocks in contact sliding down an inclined surface of inclination 30^(@) . The friction coefficient between block of mass 2 kg and the incline is mu_(1) = 0.20 and that between the block of mass 4kg and the incline is mu_(2) = 0.30 .Find the acceleration of 2.0 kg block g = 10 ms^(-2)

Figure shows two blocks in contact placed on an incline of angle theta = 30^(@) . The coefficient of friction between the block of mass 4 kg and the incline is m1, and that between 2 kg block and incline is mu_(2) . Find the acceleration of the blocks and the contact force between them if – (a) mu_(1) = 0.5 , mu_(2) = 0.8 (b) mu_(1) = 0.8 , mu_(2) = 0.5 (c) mu_(1) = 0.6 , mu_(2) = 0.1 " " [ Take g = 10m//s^(2) ]

Two blocks 4 kg and 2 kg are sliding down an incline plane as shown in figure. The acceleration of 2 kg block is.

Two blocks 4 kg and 2 kg are sliding down an incline plane as shown in fig The acceleration of 2 kg block is:

Two blocks 4 kg and 2 kg are sliding down an inclined plane as shown in the figure. The acceleration of 2kg block is

A block slides down a rough inclined plane of inclination 45^(@) . If the coefficent of kinetic friction is 0.5 , find the acceleration of the sliding block . (g=10ms^(-2)) .