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int(pi/6)^( pi/2)(cos x)/(sin^(2)x)dx...

`int_(pi/6)^( pi/2)(cos x)/(sin^(2)x)dx`

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int_(pi//6)^(pi//2) cos x dx

int_(pi//6)^(pi//2) cos x dx

int_(-pi//2)^(pi//2)(sin^(4)x)/(sin^(4)x + cos^(4)x)dx=

int_(pi//6)^(pi//3) (sin^(3) x)/(sin^(3) x + cos^(3) x) dx=

int_(pi//6)^(pi//3)(sin^(3)x)/(sin^(3)x+cos^(3)x)dx=

int_(-pi/2)^(pi/2)(a cos^(2)x+b sin^(2)x)dx

If int_(0)^(pi//2) sin^(4) x cos^(2)x dx = (pi)/(32) then int_(0)^(pi//2) cos^(4) x sin^(2) x dx=

u,=int_(0)^((pi)/(2))cos((2 pi)/(3)sin^(2)x)dx and v,=int_(0)^((pi)/(2))cos((pi)/(3)sin x)dx

If A=int_(0)^( pi)(cos x)/((x+2)^(2))dx, then int_(0)^( pi/2)(sin2x)/(x+1)dx is equal to