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The vapour pressure of pure liquids A an...

The vapour pressure of pure liquids A and B at 400 K are 450 and 700 mmHg respectively. Find out the composition of liquid mixture if total vapour pressure at this temperature is 600 mmHg.

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The vapour pressure of pure liquids A and B are 450 and 700mm Hg respectively at 350K. Find out the composition of the liquid mixture if total vapour pressure observed is 600mm Hg.

The vapour pressure of pure liquids A and B are 450 and 700 mm Hg at 350 K respectively. Find out the composition of the liquid mixture if total vapour pressure is 600 mm Hg. Also find the composition of the vapour phase.

The vapour pressure of pure liquids A and B are 450 and 700 mm Hg respectively, at 350 K. Find out the composition of the liquid mixture if total vapour pressure is 600 mm Hg. Also find the composition of the vapour phase. Apply Raoult's law P_(T)=P_(A)^(0)x_(A)+P_(B)^(0)x_(B)=P_(B)^(0)x_(A)+P_(B)^(0)(1-x_(A)) to calculate mole fraction of A(x_(A)) and B(x_(B)) . In vapour phase, partial pressure are used insted of number of moles.

The vapour pressure of pure liquids A and B are 450 and 700mm Hg respectively, at 350K.Find out the composition of the liquid mixture if total vapour pressure is 600 mm Hg. Also find the composition of the vapure phase.

The vapour pressure of pure liquids A and B is 450 and 700mm Hg , respectively, at 350K. Find out the composition of the liquid mixture if the total vapour pressure is 600mm Hg . Also find the composition of the vapour phase.