A rod of mass `M = 5kg` and length `L = 1.5 m` is held vertical on a table as shown. A gentle push is given to it and it starts falling. Friction is large enough to prevent end A from slipping on the table.

(a) Find the sum of linear momentum of all the particles of the rod when it rotates through an angle `theta = 37^(@)`
(b) Find the friction force and normal reaction force by the table on the rod, when `theta = 37^(@)`
(c) Find value of angle q when the friction force becomes zero.
`[tan 37^(@) = (3)/(4) " and " g = 10 m//s]`

Answer

(a) `7.5 kg m//s`
(b) `f = 9 N, N = 24.5 N`
(c) `cos^(-1) ((2)/(3))`