A small car took off a ramp at a speed of `30 m//s`. Immediately after leaving the ramp, the driver applied brakes on all the wheels. The brakes retarded the wheels uniformly to bring them to rest in 2 second. Calculate the angle by which the car will rotate about its centre of mass in the 2 second interval after leaving the ramp. Radius of each wheel is `r = 0.30 m` . Moment of inertia of the car along with the driver, about the relevant axis through its centre of mass is `I_(M) = 80 kg m^(2)` and the moment of inertia of each pair of wheels about their respective axles is `0.3 kg m^(2)`. Assume that the car remained in air for more than 2 second . Also assume that before take- off the wheels rolled without sliding.

Answer

`(3)/(40 rad ~= 43^(@)`