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A disc of mass M = 2m and radius R is pi...

A disc of mass M = 2m and radius R is pivoted at its centre. The disc is free to rotate in the vertical plane about its horizontal axis through its centre O. A particle of mass m is stuck on the periphery of the disc. Find the frequency of small oscillations of the system about its equilibrium position.

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The correct Answer is:
`f=(1)/(2pi) sqrt((g)/(2R))`
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