A hydrogen atom in ground state is moving with a kinetic energy of 30 eV. It collides with a deuterium atom in ground state at rest. The hydrogen atom is scattered at right angle to its original line of motion. Assume that energy of `n^(th)` state in both the atoms is given by `E_(n) = -(13.6)/(n^(2)) eV` and the mass of deuterium is twice that of hydrogen. Write the maximum and minimum possible kinetic energy of deuterium after collision.

Answer

`20 eV, 13.2 eV`