A diatomic molecule moving at a speed u absorbs a photon of wavelenght `lambda` and then dissociates into two identical atoms. One of the atoms is found to be moving with a speed v in a direction perpendicualr to the initial direction of motion of the molecule. Take mass of the molecule to be M and calculate the binding energy of the molecule. Assume that momentum of absorbed photon is negligible compared to that of the molecule.

Answer

`BE=(hc)/(lambda)-(1)/(2)Mu^(2)-(1)/(2)Mv^(2)`