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U^(238) decays in 14 steps that together...

`U^(238)` decays in 14 steps that together consitute the net reaction
`._(92)U^(238)rarr._(82)^(206)Pb+_...+6vecv+8(._(2)^(4)He)`
(a) Fill in the blank in the above reaction.
(b) The atomic masses of `U^(238),Pb^(206)` and `He^(4)` are 238.050783u. 205.97449u, and 4.002603u respectively. The energy equivalent of mass of one electron is 0.51 MeV. with this data calculate the Q value of the reaction.
(c) `U^(238)` has a long half life of `t=4.47xx10^(9)` yr. the other members in the chain reaction have relatively small half lives. As soon as a nucleus of `U^(238)` decays the remaining steps are completed almost instataneously. with this assumption, calculate the power output from a 100kg block of pure `U^(238)`. the density of `U^(238)` is 18700 `Kg//m^(3)`.

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Verified by Experts

The correct Answer is:
(a) `6._(-1)^(0)e` (b) 51.71MeV
(c) 0.01 Watt.
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