Home
Class 12
CHEMISTRY
The degree of dissociation is 0.4 at 400...

The degree of dissociation is `0.4` at `400 K` and `1.0` atm for the gaseous reaction
`PCl_(5) hArr PCl_(3)+Cl_(2)`
assuming ideal behaviour of all gases, calculate the density of equilibrium mixture at `400 K` and `1.0` atm (relative atomic mass of P is `31.0` and of Cl is `35.5`).

Text Solution

Verified by Experts

The correct Answer is:
1.2
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL AND IONIC EQUILIBRIUM

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise OBJECTIVE_TYPE|3 Videos
  • CHEMICAL AND IONIC EQUILIBRIUM

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise COMPREHENSION_TYPE|3 Videos
  • CARBOXYLIC ACID AND THEIR DERIVATIVES

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise CHAPTER TEST|3 Videos
  • CHEMICAL BONDING

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise MATCH THE COLUMN|1 Videos

Similar Questions

Explore conceptually related problems

The degree of dissociation is 0.5 at 800K and 2 atm for the gaseous reaction PCI_(5)hArrPCI_(3)+CI_(2) Assuming ideal behaviour of all the gases. Calculate the density of equilibrium mixture at 800K "and" 2 atm.

The degree of dissociation is 0.4 at 420 K and 1.0 atm for the gaseous reaction PCl_(5)(g)rarrPCl_(3)(g)+Cl_(2)(g) . Assuming ideal behaviour of all gases, calculate the density of equilibrium mixture at 420 K and 1.0 atm. (P = 31, Cl = 35.3)

PCl_(5) is 10% dissociated at 1 atm . What is % dissociation at 4 atm . PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)

For PCl_(5)hArr PCl_(3)+Cl_(2) , initial concentration of each reactant and product is 1 M. If K_(eq)=0.41 then

Show that degree of dissociation (alpha) for the dissociation of PCl_(5) " into " PCl_(3)" and " Cl_(2) at pressure P is given by alpha = [(kp)/(P+ kp)]^(1//2)