Home
Class 12
CHEMISTRY
The equilibrium constant K(p) of the rea...

The equilibrium constant `K_(p)` of the reaction: `2SO_(2)+O_(2) hArr 2SO_(3)` is `900 atm^(-1)` at `800 K`. A mixture constaining `SO_(3)` and `O_(2)` having initial pressure of 1 atm and 2 atm respectively, is heated at constant volume to equilibriate. Calculate the partial pressure of each gas at `800 K` at equilibrium.

Text Solution

Verified by Experts

The correct Answer is:
NA
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL AND IONIC EQUILIBRIUM

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise OBJECTIVE_TYPE|3 Videos
  • CHEMICAL AND IONIC EQUILIBRIUM

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise COMPREHENSION_TYPE|3 Videos
  • CARBOXYLIC ACID AND THEIR DERIVATIVES

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise CHAPTER TEST|3 Videos
  • CHEMICAL BONDING

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise MATCH THE COLUMN|1 Videos

Similar Questions

Explore conceptually related problems

The equilibrium constant for the reaction 2SO_(2(g)) + O_(2(g)) rarr 2SO_(3(g)) is 5. If the equilibrium mixture contains equal moles of SO_(3) and SO_(2) , the equilibrium partial pressure of O_(2) gas is

The equilibrium constant, K_(p) for the reaction 2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g) is 44.0atm^(-1) "at" 1000 K . What would be the partial pressure of O_(2) if at equilibrium the amound of SO_(2) and SO_(3) is the same?

The equilibrium constant (K_(p)) for the reaction, 2SO_(2)+O_(2)hArr2SO_(3) at 1000 K is 3.5 . The partial pressure of oxygen gas to give equal mole of SO_(2) and SO_(3) is :

The equilibrium constant K_p for the reaction 2SO_(2)+O_(2) Leftrightarrow 2SO_(3) is 2.5 atm ""^(-1). What would be the partial pressure of O_2 at equilibrium. If the equilibrium pressures of SO_(2) and SO_(3) are equal

The equilibrium constant for the reaction: 2SO_2(g) +O_2(g) hArr 2SO_3(g) is 256 at 1000 K. What is the value of K for the reaction: SO_3(g)hArr SO_2(g) + 1/2O_2(g) at the same temperature.

The equilibrium constant of the reaction, SO_(3)(g) hArr SO_(2)(g)+1//2 O_(2)(g) is 0.15 at 900 K . Calculate the equilibrium constant for 2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g)

The equilibrium constant of the reaction SO_(2)(g) + 1//2O_(2)(g)hArrSO_(3)(g) is 4xx10^(3)atm^(-1//2) . The equilibrium constant of the reaction 2SO_(3)(g)hArr2SO_(2)(g) + O_(2) would be: