Home
Class 12
CHEMISTRY
The K(SP)of Ca(OH)(2)is 4.42xx10^(-5)at ...

The `K_(SP)of Ca(OH)_(2)is 4.42xx10^(-5)at 25^(@)C`. A 500 mL of saturated solution of `Ca(OH)_(2)` is mixed with equal volume of `0.4M NaOH`. How much `Ca(OH)_(2)` in mg is preciptated ?

Text Solution

Verified by Experts

The correct Answer is:
NA
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL AND IONIC EQUILIBRIUM

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise OBJECTIVE_TYPE|3 Videos
  • CHEMICAL AND IONIC EQUILIBRIUM

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise COMPREHENSION_TYPE|3 Videos
  • CARBOXYLIC ACID AND THEIR DERIVATIVES

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise CHAPTER TEST|3 Videos
  • CHEMICAL BONDING

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise MATCH THE COLUMN|1 Videos

Similar Questions

Explore conceptually related problems

The K_(sp) of Ca(OH)_(2) is 4.42 xx 10^(-5) at 25^(@)C . A 500 ml of saturated solution of Ca(OH)_(2) is mixed with an equal volume of 0.4M NaOH . How much Ca(OH)_(2) in mg is precipitated ?

The solubility product ( K_(sp) ) of Ca(OH)_(2) at 25^@ is 4.42xx10^(-5) . A 500 mL of saturated solution of Ca(OH)_(2) is mixed with equal volume of 0.4 M NaOH. How much Ca(OH)_(2) in milligrams is precipitated? At equilibrium, the solution contains 0.0358 mole of K_(2)CO_(3) . Assuming the degree of dissociation of K_(2)C_(2)O_(4) and K_(2)CO_(3) to be equal, calculate the solubility product of Ag_(2)CO_(3) .

pH of a saturated solution of M (OH)_(2) is 13 . Hence K_(sp) of M(OH)_(2) is :

pH of a saturated solution of Ca(OH)_(2) is 9. the solubility product (K_(sp)) of Ca(OH)_(2) is

Ca(OH)_(2) in an example of

The pH of M/(100) Ca(OH)_2 is

The pH of Ca(OH)_(2) is 10.6 at 25^(@)C. K_(sp) of Ca(OH)_(2) is