Calculate the euilibrium constant for the reaction,
`2Fe^(3+) + 3I^(-) hArr 2Fe^(2+) + I_(3)^(-)`.
The standard reduction potential in acidic conditions are `0.77 V ` and `0.54 V` respectivelu for `Fe^(3+)//Fe^(2+)` and `I_(3)^(-)//I^(-)` couples.

Calculate the equilibrium constant for the reaction, 2Fe^(3+)+3I^(-)hArr2Fe^(2+)+I_(3)^(-) , the standard reduction potentials in acidic conditions are 0.77V and 0.54V respectively for Fe^(3+)//Fe^(2+) and I_(3)^(-)//I^(-) couples.

Calculate the equilibrium constant for the reaction. 2Fe^(2+) + 3I^(-) hArr 2Fe^(3+) + I_(3)^(-) The standard reduction potential in acidic condition is 0.78 V and 0.54 V , respectively . For Fe^(3+) //Fe^(2+) and I_(3)^(-) //I couples.

Calculate the equilibrium constant for the reaction : 2Fe^(3+)+3I^(-)hArr 2Fe^(2+)+I_(3)^(-) . Given: Standard reduction potential in acidic conditions is 0.78 V and 0.54 V, respectively, for Fe^(3+)|Fe^(2+) and I_(3)^(-)|I^(-) couples.

Calculate the equilibrium constant for the reaction : 2Fe^(3+)+3I^(Θ)hArr2Fe^(2+)+I_(3)^(Θ) The standard reduction potential in acidic conditions is 0.78V and 0.54V , respectively, for Fe^(3+)|Fe^(2+) and I_(3)^(c-)|I^(c-) couples

Calculate the equilibrium constant for the reaction. 2Fe^(3+)+3I^-harr2Fe^2+I_3^- The standary reduction potentials in acidic conditions are 0.77V and 0.54V respectively for Fe^(3+)//Fe^(2+) and I_3^-//I^- couples.

Reaction : 2Fe^(3+)+3I^(-) hArr 2Fe^(2+) + I_3^(-) The standard reduction potentials in acidic conditions are 0.77 V and 0.54 V respectively for cathodic and anodic reactions. The equilibrium constant for the reaction is approximately . (Given 10^(7.79) = 6.26 xx10^7)