In a crystalline solid, atoms of X form fcc packing and atoms of Y occupy all octahedral voids. If all the atoms along one body diagonal are removed, what is the simplest formula of the crystalline lattice solid?

In a crystalline solid, atom of A form fcc packing and atoms of B occupy all octahedral voids. If all the atoms along one body diagonal are removed then what will be the simplest formula of the crystalline solid ?

In a crystalline solid,atoms of X from fcc packing and the atoms of Y occupy all octahedral voids.If the atoms along one body diagnal are removed then the simplest formula of the crystalline solid will be:

A crystal is made of particles X and Y.X form fcc packing and Y occupies all the octahedral voids . If all the particles along one body diagonal are removed then the formula of the crystal would de :

A crystal is made of particles X and Y.X form fcc packing and Y occupies all the octahedral voids . If all the particles along one body diagonal are removed then the formula of the crystal would de :

A crystal is made up of particals X , Y , and Z . X froms fcc packing. Y occupies all octahedral voids of X and Z occupies all tetrahedral voids of X . If all the particles along one body diagonal are removed. Then the fromula of the crystal would be

A crystal is made up of particals X , Y , and Z . X froms fcc packing. Y occupies all octahedral voids of X and Z occupies all tetrahedral voids of X . If all the particles along one body diagonal are removed. Then the fromula of the crystal would be

A crystal is made up of particals X , Y , and Z . X froms fcc packing. Y occupies all octahedral voids of X and Z occupies all tetrahedral voids of X . If all the particles along one body diagonal are removed. Then the fromula of the crystal would be

A crystalline solid is made of X, Y and Z elements. Atoms of X form fcc packing , atoms of Y occupy octahedral voids while atoms of Z occupy tetrahedral voids. What will be the simplest formula of solid if atoms along one body diagonal are removed ?