A particle is projected under gravity at an angle of projection `45^(@)` with horizontal. Its horizontal range is `36m`. Find maximum Height attained by particle.

A particle is projected with velocity of 10m/s at an angle of 15° with horizontal.The horizontal range will be (g = 10m/s^2)

A particle is projected with velocity of 10m/s at an angle of 15° with horizontal.The horizontal range will be (g = 10m/s^2)

A particle is thrown with speed of 50 m//s at an angle of projection 37^(@) with the horizontal. Find (a) the time of flight, (b) the maximum height attained and ( c) the horizontal range. (sin 37^(@) = (3)/(5), cos 37^(@) = (4)/(5))

An object is projected at an angle of 45^(@) with the horizontal. The horizontal range and the maximum height reached will be in the ratio.

An object is projected at an angle of 45^(@) with the horizontal. The horizontal range and the maximum height reached will be in the ratio.

A body is projected from ground with velocity u making an angle theta with horizontal. Horizontal range of body is four time to maximum height attained by body. Find out (i) angle of projection (ii) Range and maximum height in terms of u (iii) ratio of kinetic energy to potential energy of body at maximum height

A body is projected from ground with velocity u making an angle theta with horizontal. Horizontal range of body is four time to maximum height attained by body. Find out (i) angle of projection (ii) Range and maximum height in terms of u (iii) ratio of kinetic energy to potential energy of body at maximum height

A body is projected from ground with velocity u making an angle theta with horizontal. Horizontal range of body is four time to maximum height attained by body. Find out (i) angle of projection (ii) Range and maximum height in terms of u (iii) ratio of kinetic energy to potential energy of body at maximum height

Find the angle of projection so that a body when projected has the horizontal range equal to the maximum height attained.