If three angles A, B, and C are in A.P. prove that: `cot B=(s in A-s in C)/(cos C-cos A)`

If three angles A, B, and C are in A.P. prove that: cot B=(sin A-sin C)/(cos C-cos A)

If the angles A,B,C are in A.P., prove that cot B=("sin" A-"sin" C)/(cos C-cos A)

If the angles A, B, C are in A.P., prove that cot B = (sin A-sin C)/(cos C-cosA) .

If A,B,C are in A.P then (sin A-sin C)/(cos C-cos A)=

If A,B,C are in A.P., then correct relation is cot A=(sin B+sin C)/(cos C+sin B)

If angles A,B,C are in A.P . , then 2cos (( A-C)/( 2))=

If the side lengths a,b and c are in A.P. prove that cot (A/2),cot (B/2),cot (C/2) are in A.P .

If the side lengths a,b and c are in A.P. then prove that cos ((A-C)/2) = 2sin (B/2)

If a is the smallest side of a triangle and a,b,c are in A.P. prove that "cos" A=(4c-3b)/(2c)

If A , B , C are in A.P. then (sin A-sin C)/(cos C-cos A)= adot t a n B b. cot B c. t a n2B d. none of these