A force `F` is applied on a block of mass `5 kg` as shown in figure. Co-efficient of friction between the wall and clock is `(sqrt(3))/(2). (g = 10m//s^(2))`

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A force F" is applied on a block of mass 5 kg as shown in figure. Co-efficient of friction between the wall and clock is (sqrt(3))/(2). (g = 10m//s^(2)) If 'f_(1)" and 'f_(2)' are magnitude of frictional force on the block when F = 40 N and F = 140 N repesctively. Then choose correct options

A force F" is applied on a block of mass 5 kg as shown in figure. Co-efficient of friction between the wall and clock is (sqrt(3))/(2). (g = 10m//s^(2)) If 'f_(1)" and 'f_(2)' are magnitude of frictional force on the block when F = 40 N and F = 140 N repesctively. Then choose correct options

A force of 100N is applied on a block of mass 3 kg as shown in the figure-2.164. The coefficient of friction between the surface and the block is 0.25.The frictional force acting on the block is: (Take g=10m/s^(2) )

A block of mass m is placed on another block of mass M lying on a smooth horizontal surface as shown in the figure. The co-efficient of friction between the blocks is mu . Find the maximum horizontal force F (in Newton) that can be applied to the block M so that the blocks together with same acceleration? (M=3kg, m=2kg, mu=0.1, g=10m//s^(2))

A block of mass m is placed on another block of mass M lying on a smooth horizontal surface as shown in the figure. The co-efficient of friction between the blocks is mu . Find the maximum horizontal force F (in Newton) that can be applied to the block M so that the blocks together with same acceleration? (M=3kg, m=2kg, mu=0.1, g=10m//s^(2))

A force F=75 N is applied on a block of mass 5 kg along the fixed smooth incline as as shown in the figure. Here gravitational acceleration g = 10 m s^(-2) . The acceleration of the block is

A force F=75 N is applied on a block of mass 5 kg along the fixed smooth incline as as shown in the figure. Here gravitational acceleration g = 10 m s^(-2) . The acceleration of the block is

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 3 N is applied on the block as shown in figure. The force of friction between the block and the floor is (Take g=10 m s^(-2) )