Compound `X` (molecular formula `C_5 H_8 O`) does not react appreciably with Lucas reagent at room temperature but gives a precipitate with amononiacal silver nitrate with excess of `MeMgBr, 0.42 gm` of `X` gives `224 ml` of `CH_4` at `S.T.P` Treatment of `X` with `H_2`. in the presence of `Pt` catalyst followed by boiling with excess of `HI`, gives n-pentane. Suggest the structure for `X` and write the equations involved.

Compound 'A' of molecular formula C_(4)H_(10)O on treatment with Lucas reagent at room temperature gives compound 'B'. When compound 'B' is heated with alcoholic KOH, it gives isobutan. Compound 'A' and 'B' are respectively :

An organic compound of molecular formula C_4H_10O does not react with sodium. With excess of HI, it gives only one type of alkyl halide. The compound is

Three compounds A, B, and C are isomers of the formula C_5H_8 . All of them decolourise bromine in C Cl_4 and give a positive test with Baeyer's reagent. All three compounds dissolve in cone. H_2SO_4 . Compound A gives a white precipitate with ammoniacal silver nitrate, whereas compounds B and C do not react with it. On hydrogenation, in the presence of platinum catalyst, both compounds A and B yield n-pentane, whereas compound C gives a product of formula C_5H_(10) . On oxidation with hot acidified KMnO_4 , B gave acetic acid and CH_3CH_2COOH . Identify compounds A, B, and C.