A substance will be deliquescent if its vapour pressure is:

A substance shows the phenomenon of deliquescene if its vapour pressure _____that of water vapour in air .

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

The vapour pressure of pure liquid solvent A is 0.80 atm.When a non volatile substances B is added to the solvent, its vapour pressure drops to 0.60 atm. Mole fraction of the components B in the solution is:

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

The vapour pressure of pure liquid solvent A is 0.80 atm.When a non volatile substances B is added to the solvent, its vapour pressure drops to 0.60 atm. Mole fraction of the components B in the solution is:

A liquid boils when its vapour pressure equals

The vapour pressure of pure liquid is 1.2 atm. When a non-volatile substance B is mixed in A, then its vapour pressure becomes 0.6 atm. The mole fraction of B in the solution is

When a substance is dissolved in a solvent the vapour pressure of solvent decreases. This brings: