An unknown quantity `''alpha''` is expressed as `alpha = (2ma)/(beta) log(1+(2betal)/(ma))` where m = mass, a = acceleration `l` = length, The unit of `alpha` should be

Dimensions of an unknown quantity , phi = (ma)/(alpha) log (1 +(alpha l)/(ma)) where m = mass, a= acceleration and l = "length" are

In a book, the answer for a particular question is expressed as b=(ma)/(k)[sqrt(1+(2kl)/(ma))] here m represents mass, a represent acceleration, l represent length. The unit of b should be :-

In a book, the answer for a particular question is expressed as b=(ma)/(k)[sqrt(1+(2kl)/(ma))] here m represents mass, a represent acceleration, l represent length. The unit of b should be :-

In a book, the answer for a particular question is expressed as b=(ma)/(k)[sqrt(1+(2kl)/(ma))] here m represents mass, a represent acceleration, l represent length. The unit of b should be :-

In a book, the answer for a particular question is expressed as. b=(ma)/(l)[sqrt(1+(2kl)/(ma)] . Here m represents mass, 'a' represents acceleration, l represents length. The unit of 'b' should be in SI system)

If sin (alpha - beta) =1/2 and cos (alpha + beta) =1/2, where alpha and beta are positive acute angles, then alpha and beta are

If sin (alpha - beta) =1/2 and cos (alpha + beta) =1/2, where alpha and beta are positive acute angles, then alpha and beta are

The angles alpha and beta are such that tan alpha=m+2. and tan beta=m where m is a constant.If sec^(2)alpha-sec^(2)beta=16 then the value of cot(alpha-beta) is equal to

The angles alpha and beta are such that tan alpha=m+2 and tan beta=m where m is a constant.If sec^(2)alpha-sec^(2)beta=16 then the value of cot(alpha-beta) is equal to