Equivalent conductivity of `Fe_(2)(SO_(4))_(3)` is relative to molar conductivity by the expression `:`

The resistance and conductivity of 0.02 M KCl solution are 82.4 ohm and 0.002768 S cm^(-1) respectively . When filled with 0.005 N K_(2)SO_(4) , the solution had a resistance of 324ohm . Calculate : a. Cell constant b. Conductance of K_(2)SO_(4) solution c. Conductivity of K_(2)SO_(4) solution d. Equivalent conductivity of K_(2)SO_(4) solution e. Molar conductivity of K_(2)SO_(4) solution.

The resistance and conductivity of 0.02 M KCl solution are 82.4 ohm and 0.002768 S ch^(-1) respectively . When filled with 0.005 N K_(2)SO_(4) , the solution had a resistance of 324ohm . Calculate : a. Cell constant b. Conductance of K_(2)SO_(4) solution c. Conductivity of K_(2)SO_(4) solution d. Equivalent conductivity of K_(2)SO_(4) solution e. Molar conductivity of K_(20SO_(4) solution.

The resistance and conductivity of 0.02 M KCl solution are 82.4 ohm and 0.002768 S ch^(-1) respectively . When filled with 0.005 N K_(2)SO_(4) , the solution had a resistance of 324ohm . Calculate : a. Cell constant b. Conductance of K_(2)SO_(4) solution c. Conductivity of K_(2)SO_(4) solution d. Equivalent conductivity of K_(2)SO_(4) solution e. Molar conductivity of K_(20SO_(4) solution.

Equivalent conductivity|| Variation OF conductivity and molar conductivity with dilution

Select the equivalent conductivity of 1.0 M H_(2)SO_(4) , if its conductivity is 0.26 ohm^(-1) cm^(-1) :

Select the equivalent conductivity of 1.0 M H_(2)SO_(4) , if its conductivity is 0.26 ohm^(-1) cm^(-1) :

Select the equivalent conductivity of 1.0 M H_(2)SO_(4) , if its conductivity is 0.26 ohm^(-1) cm^(-1) :

The equivalent conductivity of 0.1 (M) Na_(2)SO_(4) is _________ than the equivalent conductivity of 0.01 (M) Na_(2)SO_(4) solution.