Z us P graph is plotted for 1 mole of hypothetical gas. Volume of gas at this point A is: `[R = 0.08 atm L//"mole"-K]`

P vs V graph is plotted for 1 mole of hypothetical gas. Range of a/b for this gas in (atm-L/mole). [R = 0.08 "atm-litre"//-"mle"-K]

Consider the given graph: Graph is plotted for 1 mol of gas at 400K, find slope of curve [take: R = 0.08(L-atm)/(mol-K)]

Volume of 1.5 mole of a gas at 1 atm. pressure and 273K is

For a fixed amount of a real gas when a graph of Z us P was plotted then at very high pressure slope was observed to be 0.01 atm^(-1) . At the same temperature if a graph is plotted between PV us P then for 2 moles of the gas the y intercept is found to be 40 atm-litre. Calculate excluded volume in litres for 20 moles of the real gas/

Volume of 0.5 mole of a gas at 1 atm. pressure and 273^@C is

0.1 mole of an ideal gas has volume 1 dm^3 in a locked box with friction less piston. The gas is in thermal equilibrium with excess of 0.5 m aqueous ethylene glycol at its freezing point. If piston is released all of a sudden at 1 atm then determine the final volume of gas in dm^3 (R = 0.08 atm L mol^(–1) K ^(–1) K_f = 2.0 K molal ^(–1) ) .

The volume of 10 "moles" of an ideal gas at 10 atm and 500 K is