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Two particle are moving with velocity `vec(v)_(1)=hati-2t hatj+hatkm//s` and `vec(v)_(2)=4thati+t hatj+3hatk m//s` respectively. Time at which they are moving perpendicular to each other is ____________ (sec). (Round off to nearest integer).

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The correct Answer is:
`0003`
`vec(V)_(1).vec(V)_(2)=0`
`4t-2t^(2)+3=-0`
`t=(-4+pmsqrt(16+4xx2xx3))/(2xx-2)=(-4pmsqrt(40))/(-4)`
`t=1+sqrt(40/16)~~2.6`
or `t=1-sqrt(5/2) to ` Not possible
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