Consider the shown arrangement. The coefficient of friction between the two blocks is 0.5 . There is no friction between the 4 kg block and of 12 N is applied on the 2 kg block as shown in the figure, the acceleration of the 4 kg block would be

Options

A. `2.5 m//s^(2)`
B. `2 m//s^(2)`
C. `5 m//s^(2)`
D. None

Answer

2

Explanation

12-f=2a

f=4a
`a=2m//s^(2) rArr f=8 N`
`f le mu N=0.5xx2xx10 =10 N`