Boxes A and B are sliding to the right across a frictionless table. The hand H is slowing them down. The mass of A is larger than the mass of B. rank in order, from largest to samllest, the horizontal forces on A,B and H.

Options

A. `F_("B on H")=F_("H on B")=F_("A on B")=F_(" B on A")`
B. `F_("B on H")=F_("H on B") gt F_("A on B")=F_(" B on A")`
C. `F_("B on H")=F_("H on B")lt F_("A on B")=F_(" B on A")`
D. `F_("B on H")=F_("H on B") gt F_("A on B") gtF_(" B on A")`

Answer

2

Explanation

`F_(B on H)=F_(H on B )` and `F_(A on B)=F_(B on A)` because therse are action / reaction pairs. Box B is slowing down and therefore must have a net force to the left. So from Newton's second law we also know that `F_(H on B) gt F_(A on B)`