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If speed of a particle is given by v=A/C...

If speed of a particle is given by `v=A/C sin (At+B)`, the dimension of C is

A

L

B

`L^(-1)`

C

`LT^(-1)`

D

`L^(-1)T`

Text Solution

Verified by Experts

The correct Answer is:
B

`[V]=LT^(-1) =[A/C] " " [A]T=1`
`[A]T=1 , [A]=T^(-1)`
`[T^(-1)]=([A])/([C]C)=(T^(-1))/([C])rArr [C]=L^(-1)`
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