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The angle between the vector -hati+hatj ...

The angle between the vector `-hati+hatj` and `2 hati+3hatj` is :

A

`cos theta=1/5`

B

`sin theta=sqrt(25/26)`

C

`tan theta=sqrt(5)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`cos theta=(vec(a).vec(b))/(ab) =(-2+3)/(sqrt(2)sqrt(13))=1/(sqrt(26))`
`:. sin theta=sqrt(25/26)`
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