The acceleration of particle at position x is given by a=3-2x. If the particle is rest at x=0, at what value of x is it at rest again ?

Answer

3

Explanation

`a=3-2x`
`(vdv)/(dx)=3-2x`
`(v^(2))/2=3-2x`
`(v^(2))/2 =3-2x`
`rArr v^(2)=3x-x^(2)+C`
`rArr v^(2)=3x-x^(2)=x(3-x)`
v=0 at x=0, x=3