Two cars stat to move simultaneously with the same speed from point A to point B. The first moves in a straight line connecting A and B, uniformly, and the second-on the bypass road, made as a half-circle connecting the same points. The speed of the second uniformly increases so that the end of the path its speed is doubled. which car will arrive earlier at point B ?

Options

A. 1 st car
B. 2 nd car
C. both will reach simultaneously
D. depends on values of R and v

Answer

C

Explanation

`t_(1)=(2R)/v`
for 2nd car, `v_(av)=(v+2v)/2=(piR)/(t_(2))`
`rArr t_(2)=(2piR)/(3v) gt t_(1)`