A particle whose mass is m=500 g, is acted upon by two constant forces , 2N and 3N. By their action it moves with acceleration `a=2sqrt(19) m//s^(2)`

Options

A. The angles between these force is `60^(@)`
B. If the initial velocity of the particle is along 2N force, it will move in a straigt line
C. IF the initial velocity of the particle is along 3N force, it will move is a parabolic path.
D. The particle can move in a straight line if its initial velocity is zero

Answer

AC

Explanation

`f=ma =sqrt(19) =sqrt(2^(2)+3^(2)+2xx3xx2 cos theta)`
`19=4+9+12 cos theta`
`cos theta=1/2`