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A point moves in the XY planes such that...

A point moves in the XY planes such that its component of velocity along the is always 0.5 m/s, so that the trajectory equation has the form `y=2x^(2)+x^(3)`. Find the velocity (in m/s) of the particle at x=1. fill `vsqrt(2)` in OMR sheet.

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The correct Answer is:
8
`(dy)/(dt)=(4x+3x^(2))(dx)/(dt)`
`v_(y)=7/2 m//s`
`v=sqrt(49/4+1/4)=(6sqrt(2))/2=5/(sqrt(2)) m//s`
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