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Two balls are thrown simultaneously at two different angles so that both have equal ranges. If `H_(1)` and `H_(2)` be the maximum heights attained in two cases. Then the summation `H_(1)+H_(2)` is equal to

A

`(v_(0)^(2))/(2g)`

B

`(v_(0)^(2))/g`

C

`(2v_(0)^(2))/g`

D

`(v_(0)^(2))/(4g)`

Text Solution

Verified by Experts

The correct Answer is:
1

`H_(1)+H_(2)=(v_(0)^(2))/(2g) (sin^(2) theta+cos^(2)theta)`
`rArr theta_(1)+theta_(2)=90^(@)=(v_(0)^(2))/(2g)`
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