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A particle is constrained to move in a circle with a 10 -meter radius. At one instant, the particle's speed is 10 m/s and is increasing at a rate of `10 m//s^(2)`. The angle between the particle's velocity and acceleration vectors is

A

`0^(@)`

B

`30^(@)`

C

`45^(@)`

D

`60^(@)`

Text Solution

Verified by Experts

The correct Answer is:
3

`(v^(2))/R=10`
`a_(1)=0`
angle is `45^(@)`
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