In figure shown, both blocks are released from rest. Length of 4 kg block is 2 m and of 1 K g is 4 m . Find the time they take to cross each other ? Assume pulley to be light and string to be light and inelastic .

Answer

1

Explanation

`4g-T=4a.....(1)`
`T-1g=1xxa...(2)`
After solving (1) and (2) `a=(3g)/5`
acceleration of A w.r.t. B
`a_(A//B)=(6g)/5=12 m//s^(2)`
If A will across B then distance travelled by A w.r.t B is 6 m
`6=0+1/2 xx12xxt^(2), t=1 sec`