System is released from rest. If all contacts surface are smooth, the speed acquired by M (in m/s) when small ball m just touches the floor is (take m =1 kg, M=2 kg , h=30 cm)

Answer

1

Explanation

`w_(g)=1/2 mv^(2)+1/2 Mv_(1)^(2) =mgh`
`mv=Mv_(1)`
`v=(2xxv_(1))/1`
`1/2xx1xx4v_(1)^(2)+1/2xx2xxv_(1)^(2)=1xx10xx0.3`
`v_(1)=1 m//s`