With what angular velocity `omega` (in rad/s) should we rotate the disc so that a mass hanging on to the periphery by a thread of length l =35/24m is deviated from the vertical by an angle `alpha=37^(@)` in steady state(fig).? Radius of the disc R=1 m

Answer

2

Explanation

`T cosa= mg `

`T sin a =m omega^(1)r`
`tan alpha=(omega^(2)r)/g`
`omega=sqrt((g tan alpha)/r) =sqrt((10xx3/4)/(35/24xx3/5+1))=sqrt(15/2)/(15/8))`
=2rad/s