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A solid sphere of mass m & radius R is c...

A solid sphere of mass m & radius R is cut into two equal parts and kept as shown. Find the height of centre of mass from the ground.

A

`R/2`

B

`(3R)/8`

C

`(7R)/8`

D

`(9R)/8`

Text Solution

Verified by Experts

The correct Answer is:
C

`y_(cm)=(m/2xx(3R)/8+m/2xx((3R)/8+R))/m`
`(3R)/16+(3R)/16+R/2`
`=(3R+4R)/8=(7R)/8`
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