A juggler tosses a ball up in the air with initial speed u. at the instant it reaches its maximum height H, he tosses up a seconds ball with same initial speed. The two balls will collide at a height.

Options

A. `H/4`
B. `H/2`
C. `(3H)/4`
D. `sqrt(3/4)H`

Answer

C

Explanation

`0^(2)=u^(2)-2gH`
`u=sqrt(2gH)`
`S_(rel)=H, a_(rel)=0, u_(rel)=sqrt(2gh)`
`H=sqrt(2gH)xxt`
`t=sqrt((H)/(2g))`
`y=sqrt(2gH)xxsqrt(H/(2g))-1/2 xxH/(2g)`
`=H-H/4=(3H)/4`