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In the arrangements as shown Mgt2m. Find...

In the arrangements as shown Mgt2m. Find the extension in the spring of forces constant `K_(1)`. All pulleys are smooth and massless and the blocks do not oscillates.

A

`(Mmg)/(K_(1)(M+m))`

B

`(4Mmg).((M+m)).K/(K_(1))`

C

`(Mmg)/(K_(1)(M+2m))`

D

`(4Mmg)/(K_(1)(M+2m))`

Text Solution

Verified by Experts

The correct Answer is:
4
`a=((M-2m)g)/((M+2m))`
Now, `Mg-K_(1)x_(1)=Ma`
`x_(1)=(M(g-a))/(K_(1))`
`=(4Mmg)/(K_(1)(M+2m))`
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