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In the figure the variations of componet...

In the figure the variations of componets of acceleration of particles of mass 1kg is shown w.r.t. time. The initial velocity of the particle is `vec(u)=(-3 hati+4hatj)`m/s. the total work done by the resultant force on the particles in time intervals from t=0 to t=4 seconds is :

A

22.5J

B

10 J

C

0

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
2
Area of the graph
`int a_(x) st =6 = V_((x)f) -(-3) rArr V_((x)f) =3`
and `inta_(y) dt =-10 =V_((y)f) -(4) rArr V_((y)f)=-6`
Now work doen =`Delta KE=10 J`
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