A calorimeter of water equivalent 50 g contains 100 g water at `30^(@)C`, in each of the situations, select the option(s) that indicate the correct final temperature

Options

A. 15 g of ice at `-20 ^(@)C`, final temperature `210 //11^(@)C`
B. 5 g of steam at `100^(@)C`, final temperature `1540//31^(@)C`
C. 80 g of water at `70^(@)C` , final temperature `430//9^(@)C`
D. 15 g of ice at `0^(@)C`, final temperature `20^(@)C `

Answer

BD

Explanation

`(A) 15xx1/2xx(0-(-20))=150 cal`
`15xx80=1200 cal`
To melt we require 1350 cal
`1350+15xx1xx(T-0)=150xx1xx(30-T)`
`90+T=300-10T`
`T=210/11 .^(@)C`
(B) `5xx540+5xx1xx(100-T)`
`=150xx1xx(T-30)`
3200+4500=155 T
`T=1540/31 .^(@)C`
(C) `150(T-30)=80(70-T)`
`230 T=10100`
`T=1010/23`
(D) `15xx80+15xx1xx(T-0)=150(30-T)`
`T=20^(@)C`