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The radius of gyration of a solid shaper...

The radius of gyration of a solid shapere of radius r about a certain axis is r. The distance of this axis from the centre of the shpere is

A

r

B

0.5r

C

`sqrt(0.6) r `

D

`sqrt(0.4)r`

Text Solution

Verified by Experts

The correct Answer is:
3
`2/5 mr^(2)+mx^(2)=mr^(2)`
`rArr x=sqrt(0.6)r`
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